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Home » Thus, the remainder is $0$. - Simpleprint

Thus, the remainder is $0$. - Simpleprint

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📌 A cylindrical tank with a radius of 4 meters and a height of 10 meters is filled with water. If a spherical ball with a radius of 2 meters is submerged in the tank, by how much will the water level rise?

📌 Volume of the cylindrical tank: \( V_{\text{cylinder}} = \pi \times 4^2 \times 10 = 160\pi \) cubic meters.

📌 Volume of the spherical ball: \( V_{\text{sphere}} = \frac{4}{3} \pi \times 2^3 = \frac{32}{3}\pi \) cubic meters.

📌 Rise in water level: \( \frac{V_{\text{sphere}}}{\text{Base area of cylinder}} = \frac{\frac{32}{3}\pi}{\pi \times 4^2} = \frac{32}{3 \times 16} = \frac{2}{3} \) meters.

📌 #### \(\frac{2}{3}\) meters

📌 Perimeter equation: \( 2(w + 3w) = 64 \).

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+ 10 + r = 15
+ r = 15
r = 0
Thus, the values of \( p \), \( q \), and \( r \) are:
\boxed{p = 5, \ q = 10, \ r = 0}
\]1. 半径3米の円柱形のタンクに、毎分5立方メートルの割合で水が注入され...
円柱の体積 \( V \) は、公式 \( V = \pi r^2 h \) で与えられます。ここで...
V = \pi \times 3^2 \times 4 = 36\pi \text{ 立方メートル}
充填速度が毎分5立方メートルであるため、タンクを満たすのにかかる時間 \(...
t = \frac{36\pi}{5} \approx \frac{113.097}{5} \approx 22.619 \text{ 分...

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