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Home » This is a **circular cylinder**? No â it's quadratic. But geometrically, the surface \( - Simpleprint

This is a circular cylinder? No â it's quadratic. But geometrically, the surface \( - Simpleprint

📅 March 15, 2026 👤 scraface

Mar 15, 2026

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📌 V = s^3 = 6^3 = 216 \text{ cm}^3

📌 Thus, the volume of the cube is:

📌 \boxed{216 \text{ cm}^3}

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Let \( y = \frac{x^2 + 1}{x^2 - 1} \). Rearranging gives:
y(x^2 - 1) = x^2 + 1 \quad \Rightarrow \quad yx^2 - y = x^2 + 1.
Rearranging terms:
If \( y \neq 1 \),
x^2 = \frac{y + 1}{y - 1}.
Since \( x^2 \geq 0 \), we require:
\frac{y + 1}{y - 1} \geq 0.
Analyzing the sign of the expression:
The numerator \( y + 1 \geq 0 \Rightarrow y \geq -1 \).
The denominator \( y - 1 > 0 \Rightarrow y > 1 \), or \( y - 1 < 0 \Ri...

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