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📅 March 14, 2026 👤 scraface

Mar 14, 2026

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Substitute back: \(x = \frac{6}{5} + 3 = \frac{21}{5}\).
#### \(x = \frac{21}{5}, y = \frac{6}{5}\)
Find the derivative of \(f(x) = 4x^3 - 5x^2 + 2x - 7\).
Differentiate term by term: \(f'(x) = 12x^2 - 10x + 2\).
#### \(12x^2 - 10x + 2\)
If the sum of the first \(n\) natural numbers is 210, find \(n\).
Use the formula: \(\frac{n(n+1)}{2} = 210\).
Multiply both sides by 2: \(n(n+1) = 420\).
Solve the quadratic equation: \(n^2 + n - 420 = 0\).
Factor: \((n - 20)(n + 21) = 0\).

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