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Home » сталкивается DVD冰感 Jake Paul vs Tank: Expect the Unexplained Outcome! - Simpleprint

сталкивается DVD冰感 Jake Paul vs Tank: Expect the Unexplained Outcome! - Simpleprint

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📌 The length is \( 3 \times 8 = 24 \, \text{m} \). The area is:

📌 \[ \text{Area} = w \times \text{length} = 8 \times 24 = 192 \, \text{m}^2 \]

📌 A projectile is launched with an initial velocity of 50 m/s at an angle of 30 degrees to the horizontal. What is the horizontal range of the projectile? (Assume no air resistance and \( g = 9.8 \, \text{m/s}^2 \))

📌 The horizontal range \( R \) is given by:

📌 \[ R = \frac{v^2 \sin(2\theta)}{g} \]

📌 \[ R = \frac{50^2 \sin(60^\circ)}{9.8} \]

📌 \[ R = \frac{2500 \times \frac{\sqrt{3}}{2}}{9.8} \]

📌 \[ R \approx \frac{2500 \times 0.866}{9.8} \]

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Now compute the magnitude:
|z(t)| = \sqrt{(7\cos \omega t)^2 + (\sin \omega t)^2} = \sqrt{49\cos^...
= \sqrt{48\cos^2 \omega t + (\cos^2 \omega t + \sin^2 \omega t)} = \sq...
The maximum occurs when \( \cos^2 \omega t = 1 \):
|z(t)|_{\text{max}} = \sqrt{48 + 1} = \sqrt{49} = 7
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